In this tutorial, I'm going to
demonstrate how to serialize your own objects to and from an XML file.
Since .NET can use reflection to get
property names, basic serialization is unbelievably simple. It only gets
slightly difficult when you want to name your XML tags differently than your
property names (but still not very hard). If you've ever used an XML
serialization package in C++ like boost, tinyXML, or libXML2, you'll see how
comparatively easy C# is to use.
Let's start with a basic example.
Below is an object that stores some information about a movie.
public class Movie
{
public string Title
{ get; set; }
public int Rating
{ get; set; }
public DateTime ReleaseDate
{ get; set; }
}
{
public string Title
{ get; set; }
public int Rating
{ get; set; }
public DateTime ReleaseDate
{ get; set; }
}
All right, now that we have an
object, let's write a function that will save it to XML.
static public void SerializeToXML(Movie
movie)
{
XmlSerializer serializer = new XmlSerializer(typeof(Movie));
TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
serializer.Serialize(textWriter, movie);
textWriter.Close();
}
{
XmlSerializer serializer = new XmlSerializer(typeof(Movie));
TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
serializer.Serialize(textWriter, movie);
textWriter.Close();
}
The first thing I do is create an XMLSerializer (located in the System.Xml.Serialization namespace) that
will serialize objects of type Movie. The XMLSerializer will serialize objects
to a stream, so we'll have to create one of those next. In this case, I want to
serialize it to a file, so I create a TextWriter. I then simply call Serialize
on the XMLSerializer passing in the stream (textWriter) and the object (movie).
Lastly I close the TextWriter because you should always close opened files.
That's it! Let's create a movie object and see how this is used.
static void Main(string[] args)
{
Movie movie = new Movie();
movie.Title = "Starship Troopers";
movie.ReleaseDate = DateTime.Parse("11/7/1997");
movie.Rating = 6.9f;
SerializeToXML(movie);
}
static public void SerializeToXML(Movie movie)
{
XmlSerializer serializer = new XmlSerializer(typeof(Movie));
TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
serializer.Serialize(textWriter, movie);
textWriter.Close();
}
{
Movie movie = new Movie();
movie.Title = "Starship Troopers";
movie.ReleaseDate = DateTime.Parse("11/7/1997");
movie.Rating = 6.9f;
SerializeToXML(movie);
}
static public void SerializeToXML(Movie movie)
{
XmlSerializer serializer = new XmlSerializer(typeof(Movie));
TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
serializer.Serialize(textWriter, movie);
textWriter.Close();
}
After this code executes, we'll have
an XML file with the contents of our movie object.
<?xml version="1.0" encoding="utf-8"?>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Title>Starship Troopers</Title>
<Rating>6.9</Rating>
<ReleaseDate>1997-11-07T00:00:00</ReleaseDate>
</Movie>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Title>Starship Troopers</Title>
<Rating>6.9</Rating>
<ReleaseDate>1997-11-07T00:00:00</ReleaseDate>
</Movie>
If you noticed, all of the XML tag names
are the same as the property names. If we want to change those, we can simply
add an attribute above each property that sets the tag name.
public class Movie
{
[XmlElement("MovieName")]
public string Title
{ get; set; }
[XmlElement("MovieRating")]
public float Rating
{ get; set; }
[XmlElement("MovieReleaseDate")]
public DateTime ReleaseDate
{ get; set; }
}
{
[XmlElement("MovieName")]
public string Title
{ get; set; }
[XmlElement("MovieRating")]
public float Rating
{ get; set; }
[XmlElement("MovieReleaseDate")]
public DateTime ReleaseDate
{ get; set; }
}
Now when the same code is executed
again, we get our custom tag names.
<?xml version="1.0" encoding="utf-8"?>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<MovieName>Starship Troopers</MovieName>
<MovieRating>6.9</MovieRating>
<MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<MovieName>Starship Troopers</MovieName>
<MovieRating>6.9</MovieRating>
<MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>
Sometimes, in XML, you want
information stored as an attribute of another tag instead of a tag by itself.
This can be easily accomplished with another property attribute.
public class Movie
{
[XmlAttribute("MovieName")]
public string Title
{ get; set; }
[XmlElement("MovieRating")]
public float Rating
{ get; set; }
[XmlElement("MovieReleaseDate")]
public DateTime ReleaseDate
{ get; set; }
}
{
[XmlAttribute("MovieName")]
public string Title
{ get; set; }
[XmlElement("MovieRating")]
public float Rating
{ get; set; }
[XmlElement("MovieReleaseDate")]
public DateTime ReleaseDate
{ get; set; }
}
With this code, MovieName will now
be an attribute on the Movie tag.
<?xml version="1.0" encoding="utf-8"?>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
MovieName="Starship Troopers">
<MovieRating>6.9</MovieRating>
<MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
MovieName="Starship Troopers">
<MovieRating>6.9</MovieRating>
<MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>
Let's move on to something a little
more interesting. Let's create another movie and serialize a List of them to
our XML file. Here's the modified code to do just that:
static void Main(string[] args)
{
Movie movie = new Movie();
movie.Title = "Starship Troopers";
movie.ReleaseDate = DateTime.Parse("11/7/1997");
movie.Rating = 6.9f;
Movie movie2 = new Movie();
movie2.Title = "Ace Ventura: When Nature Calls";
movie2.ReleaseDate = DateTime.Parse("11/10/1995");
movie2.Rating = 5.4f;
List<Movie> movies = new List<Movie>() { movie, movie2 };
SerializeToXML(movies);
}
static public void SerializeToXML(List<Movie> movies)
{
XmlSerializer serializer = new XmlSerializer(typeof(List<Movie>));
TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
serializer.Serialize(textWriter, movies);
textWriter.Close();
}
{
Movie movie = new Movie();
movie.Title = "Starship Troopers";
movie.ReleaseDate = DateTime.Parse("11/7/1997");
movie.Rating = 6.9f;
Movie movie2 = new Movie();
movie2.Title = "Ace Ventura: When Nature Calls";
movie2.ReleaseDate = DateTime.Parse("11/10/1995");
movie2.Rating = 5.4f;
List<Movie> movies = new List<Movie>() { movie, movie2 };
SerializeToXML(movies);
}
static public void SerializeToXML(List<Movie> movies)
{
XmlSerializer serializer = new XmlSerializer(typeof(List<Movie>));
TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
serializer.Serialize(textWriter, movies);
textWriter.Close();
}
Now we have XML that looks like
this:
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfMovie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Movie MovieName="Starship Troopers">
<MovieRating>6.9</MovieRating>
<MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>
<Movie MovieName="Ace Ventura: When Nature Calls">
<MovieRating>5.4</MovieRating>
<MovieReleaseDate>1995-11-10T00:00:00</MovieReleaseDate>
</Movie>
</ArrayOfMovie>
<ArrayOfMovie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Movie MovieName="Starship Troopers">
<MovieRating>6.9</MovieRating>
<MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>
<Movie MovieName="Ace Ventura: When Nature Calls">
<MovieRating>5.4</MovieRating>
<MovieReleaseDate>1995-11-10T00:00:00</MovieReleaseDate>
</Movie>
</ArrayOfMovie>
Ok, so you can see how easy it is to
get your objects into an XML document. Let's now look at how to read an XML
document back into our objects - deserialization. The process of deserializing
is very similar to what we did for serialization.
static List<Movie> DeserializeFromXML()
{
XmlSerializer deserializer = new XmlSerializer(typeof(List<Movie>));
TextReader textReader = new StreamReader(@"C:\movie.xml");
List<Movie> movies;
movies = (List<Movie>)deserializer.Deserialize(textReader);
textReader.Close();
return movies;
}
{
XmlSerializer deserializer = new XmlSerializer(typeof(List<Movie>));
TextReader textReader = new StreamReader(@"C:\movie.xml");
List<Movie> movies;
movies = (List<Movie>)deserializer.Deserialize(textReader);
textReader.Close();
return movies;
}
Just like before, we first create an
XmlSerializer that can deserialize objects of type List<Movie>. The XmlSerializer
also deserializes from a stream, so we create a file stream from our XML file.
We then simply call Deserialize on the stream and cast the output to our desired type. Now
the movies List is populated with objects that we previously serialized to the
XML file.
The deserializer is very good at
handling missing pieces of information in your XML file. Let's say the second
movie didn't have the MovieName attribute on the Movie tag. When the XML file
is deserialized, it simply populates that field with null. If MovieRating
wasn't there, you'd receive 0. Since a DateTime object can't be null, if
MovieReleaseDate was missing, you'd receive DateTime.MinValue (1/1/0001
12:00:00AM).
If the XML document contains invalid
syntax, like say the first opening Movie tag was missing, the Deserialize call
will fail with an InvalidOperationException. It will also be kind enough to
specify the location in the file where it encountered the error (line number,
column number).
One thing to remember is that the
basic XML serialization won't maintain references. Let's say I populated my
movies list with the same movie reference multiple times:
Movie movie =
new Movie();
movie.Title = "Starship Troopers";
movie.ReleaseDate = DateTime.Parse("11/7/1997");
movie.Rating = 6.9f;
List<Movie> movies = new List<Movie>() { movie, movie };
movie.Title = "Starship Troopers";
movie.ReleaseDate = DateTime.Parse("11/7/1997");
movie.Rating = 6.9f;
List<Movie> movies = new List<Movie>() { movie, movie };
Now I have a list containing two of
the exact same movie reference. When I serialize and deserialize this list, it
will be converted to two separate instances of the movie object - they would
just have the same information. Along this same line, the XMLSerializer also
doesn't support circular references. If you need this kind of flexibility, you
should consider binary serialization.
There's still a lot to cover when it
comes to XML serialization, but I think this tutorial covers enough of the
basics to get things rolling. If you've got questions or anything else to say,
leave us a comment.
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